document.write( "Question 760858: how do i put this hyperbola in to standard form of ((x-h)^2/a^2)-((y-k)^2/b^2)=1 by completing the square
\n" ); document.write( "36x^2-y^2-24x+6y-91=0
\n" ); document.write( "i know i have to group the x's and y's but when i group the x's (36x^2-24x) how do i make 36x^2 just x^2 because i factored out 12 to get 12(3x^2-2x) but the 3 in from of the x^2 is really confusing me please help :( asap Thank youuu
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Algebra.Com's Answer #462887 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"36x%5E2-y%5E2-24x%2B6y-91=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"36x%5E2-24x-y%5E2%2B6y=91\"
\n" ); document.write( "\"%2836x%5E2-24x%29-%28y%5E2-6y%29=91\"
\n" ); document.write( "Now DIVIDE the x expression by 36 and indicate a factor of 36 applied to the x expression.
\n" ); document.write( "\"36%28x%5E2-%2824%2F36%29x%29-%28y%5E2-6y%29=91\"
\n" ); document.write( "\"36%28x%5E2-%282%2F3%29x%29-%28y%5E2-6y%29=91\"\r
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\n" ); document.write( "\n" ); document.write( "The missing square term for the x part is \"%282%2F%282%2A3%29%29%5E2=1%2F9\"
\n" ); document.write( "and
\n" ); document.write( "The missing square term for the y part is \"%286%2F2%29%5E3=9\"\r
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\n" ); document.write( "\n" ); document.write( "Watch the signs and factors very carefully when you ADD the square terms to both sides of the equation, because this can be the source of mistakes.
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