document.write( "Question 760826: if x varies directly as y, and x=24 when y=8, find x when y=10 \n" ); document.write( "
Algebra.Com's Answer #462870 by ramkikk66(644)\"\" \"About 
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x varies directly as y. This means that:\r
\n" ); document.write( "\n" ); document.write( "(x/y) is a constant. Let us call this constant as \"k\". i.e. \"x+%2F+y+=+k\"\r
\n" ); document.write( "\n" ); document.write( "x = 24 when y = 8\r
\n" ); document.write( "\n" ); document.write( "So \"k+=+24%2F8+=+3\"\r
\n" ); document.write( "\n" ); document.write( "When y = 10\r
\n" ); document.write( "\n" ); document.write( "\"x%2Fy+=+x%2F10+=+k+=+3\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2F10+=+3\"\r
\n" ); document.write( "\n" ); document.write( "Multiplying both sides by 10,\r
\n" ); document.write( "\n" ); document.write( "\"x+=+3%2A10+=+30\"\r
\n" ); document.write( "\n" ); document.write( "When y = 10, x = 30.\r
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