document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760795>Question 760795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Select the equation for the circle with center at point (2, –5) and a radius of 12.<BR>\n" );
document.write( "	A.(x - 2)2 + (y + 5)2 = 12		B.(x + 2)2 + (y - 5)2 = 12<BR>\n" );
document.write( "	C.(x - 2)2 + (y + 5)2 = 144		D.(x + 2)2 + (y - 5)2 = 144 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462864 by </B><A HREF=/tutors/aboutme.mpl?userid=kjmg><B>kjmg(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kjmg><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Select the equation for the circle with center at point (2, –5) and a radius of 12.<BR>\n" );
document.write( "	A.(x - 2)2 + (y + 5)2 = 12		B.(x + 2)2 + (y - 5)2 = 12<BR>\n" );
document.write( "	C.(x - 2)2 + (y + 5)2 = 144		D.(x + 2)2 + (y - 5)2 = 144\r<BR>\n" );
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document.write( "the equation of Circle is (x-h)^2 + (y-K)^2 = r^2.\r<BR>\n" );
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document.write( "(2, -5) substituting it to the equation, (x-(-2))^2 + (y-(5))^2 = (12)^2. </SPAN>\n" );
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