document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760707>Question 760707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a+6b=2 , a-3b=-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462860 by </B><A HREF=/tutors/aboutme.mpl?userid=Lavitesh><B>Lavitesh(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Lavitesh><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">    a + 6b =  2      .....(1)<BR>\n" );
document.write( "   a - 3b = -1 <BR>\n" );
document.write( "(-) (+)   (+)<BR>\n" );
document.write( "_____________<BR>\n" );
document.write( "   0 + 9b = 3<BR>\n" );
document.write( "        b = 3/9<BR>\n" );
document.write( "        b = 1/3       ....(2)<BR>\n" );
document.write( "  Putting (2) in (1) we get\r<BR>\n" );
document.write( "\n" );
document.write( "  a + 6(1/3) = 2<BR>\n" );
document.write( "  a + 2 = 2<BR>\n" );
document.write( "  a = 0<BR>\n" );
document.write( " <BR>\n" );
document.write( "Therefore a = 0   and   b = 1/3<BR>\n" );
document.write( " </SPAN>\n" );
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