document.write( "Question 760725: please show me step by step how to solve these simultaneous equations using the substitution method :
\n" ); document.write( "x-8=2y and x+y=-2
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Algebra.Com's Answer #462847 by ramkikk66(644)\"\" \"About 
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\"x+-+8+=+2y\" ---> equation (1)
\n" ); document.write( "\"x+%2B+y+=+-2\" ---> equation (2)\r
\n" ); document.write( "\n" ); document.write( "For substitution, we have to express x in terms of y. In the 1st equation, let us get rid of the term \"8\" on the left hand side, to get x alone. To do this, we have to add 8 to both sides of the equation (because there is a \"-8\" on the left side, adding 8 will cancel it out)\r
\n" ); document.write( "\n" ); document.write( "From (1), by adding 8 to both sides, we get\r
\n" ); document.write( "\n" ); document.write( "\"x+=+2y+%2B+8\" ---> equation(3)\r
\n" ); document.write( "\n" ); document.write( "Now that we know that x = 2y + 8, we substitute for x in equation (2)\r
\n" ); document.write( "\n" ); document.write( "\"2y+%2B+8+%2B+y+=+-2\" -> because x = 2y + 8\r
\n" ); document.write( "\n" ); document.write( "Simplifying\r
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\n" ); document.write( "\n" ); document.write( "\"3y+%2B+8+=+-2\" ---> equation(4)\r
\n" ); document.write( "\n" ); document.write( "Subtract 8 from both sides (to get rid of the +8 on the left side)\r
\n" ); document.write( "\n" ); document.write( "\"3y+=+-2+-8+=+-10\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-10%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Now that we know y, we can get the value of x from (3)\r
\n" ); document.write( "\n" ); document.write( "\"x+=+2y+%2B+8+=+2%2A%28-10%2F3%29+%2B+8+=+-20%2F3+%2B+8+=+-20%2F3+%2B+24%2F3+=+4%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+4%2F3\"\r
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