document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760705>Question 760705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many pounds of chamomile tea that costs $18.20 per pound must be mixed with<BR>\n" );
document.write( "12 lb of orange tea that costs $12.25 per pound to make a mixture that costs $14.63 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462843 by </B><A HREF=/tutors/aboutme.mpl?userid=2897696><B>2897696(96)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=2897696><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=2897696><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would solve this problem using a chart:<BR>\n" );
document.write( "  Type         : P (money or percentage of item):A (amount of item): Total<BR>\n" );
document.write( "C)chamomile tea:$18.20     <==multiply==>       :x    gets==>           :18.20x<BR>\n" );
document.write( "o)orange tea   :$12.25 <==multiply==>           :12  gets==>             :147.00<BR>\n" );
document.write( "m)mixture     :$14.63 <==multiply==>           :x+12 gets==>      :14.63x+175.56\r<BR>\n" );
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document.write( "Now using the information on the chart, we can make an equation. Since it is a mixture, we add both teas to make this mixture so the equation is the total of c tea and o tea=mixture of tea. Which in math is:18.20x+147.00=14.63x+175.56<BR>\n" );
document.write( "From here you simplify the equation and solve for x. \r<BR>\n" );
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document.write( "                   :)See if you can solve it from here, good luck!!;)<BR>\n" );
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