document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760672>Question 760672</A>: <I><SPAN STYLE=\"word-break: break-all;\"> graph equations using table values y=2+3x/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462820 by </B><A HREF=/tutors/aboutme.mpl?userid=2897696><B>2897696(96)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=2897696><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=2897696><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> *you should always write the equation into y=mx+b. Here the y=y values, x=x values, m=slope of line(run over rise).y=(3/4)x+2<BR>\n" );
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document.write( "TABLE METHOD: use five friends -2,-1,0,1,2 (always remember these numbers because they are your FRIENDS) plug the numbers into either the x values or y values (better as x values) lets start with -2. y=(3/4)*-2 +2 this equals 1/2(this would be the y value) so the first ordered pair you would graph is       (-2,1/2). (By the way, -2 comes from the plug in)  Anyways the next thing you do is plug in the rest of five friends and then plot the points and connect the dots. you should get a straight line. \r<BR>\n" );
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