document.write( "Question 760631: The lenght of a rectangle is 10 ft longer than twice the width.If the perimeter is 116 ft find the lenght and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #462811 by tommyt3rd(5050)![]() ![]() You can put this solution on YOUR website! l=2w+10\r \n" ); document.write( "\n" ); document.write( "P=2(l+w)=116\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so\r \n" ); document.write( "\n" ); document.write( "l+w=58\r \n" ); document.write( "\n" ); document.write( "2w+10+w=58\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3w=48\r \n" ); document.write( "\n" ); document.write( "w=16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "l=2(16)+10=42\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "length: 42 ft \n" ); document.write( "width: 16 ft \n" ); document.write( " |