document.write( "Question 760631: The lenght of a rectangle is 10 ft longer than twice the width.If the perimeter is 116 ft find the lenght and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #462811 by tommyt3rd(5050)\"\" \"About 
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l=2w+10\r
\n" ); document.write( "\n" ); document.write( "P=2(l+w)=116\r
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\n" ); document.write( "\n" ); document.write( "so\r
\n" ); document.write( "\n" ); document.write( "l+w=58\r
\n" ); document.write( "\n" ); document.write( "2w+10+w=58\r
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\n" ); document.write( "\n" ); document.write( "3w=48\r
\n" ); document.write( "\n" ); document.write( "w=16\r
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\n" ); document.write( "\n" ); document.write( "l=2(16)+10=42\r
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\n" ); document.write( "\n" ); document.write( "length: 42 ft
\n" ); document.write( "width: 16 ft
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