document.write( "Question 760616: A man is 3 times as old as his daughter, 8 years ago the product of their ages is 112, find their present ages \n" ); document.write( "
Algebra.Com's Answer #462778 by tommyt3rd(5050)![]() ![]() You can put this solution on YOUR website! Notice: \n" ); document.write( "Factors of 112 are \n" ); document.write( "1, 112 \n" ); document.write( "2, 56 \n" ); document.write( "4, 28 <--- most likely ages 8 years ago! \n" ); document.write( "7, 16 \n" ); document.write( "8, 14 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we verify... \r \n" ); document.write( "\n" ); document.write( "3(4+8)=36=28+8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so their ages are 12 and 36 \n" ); document.write( " |