document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760532>Question 760532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive terms in AP such that their sum is 36 and the third term exceeds the first and the secnd term by two<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462775 by </B><A HREF=/tutors/aboutme.mpl?userid=malglu><B>malglu(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malglu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the three terms be \r<BR>\n" );
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document.write( "x   y  and x+y+2\r<BR>\n" );
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document.write( "added altogether they = 36, so 2x+2y = 34\r<BR>\n" );
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document.write( "now in an AP there is a common difference between any two consecutive terms, so x+y+2 -  y = y-x   tidy this up and you get y=2x+2<BR>\n" );
document.write( "substitute this into 2x + 2y =34 to elliminate the y term, and you get<BR>\n" );
document.write( "6x = 30, so x =5\r<BR>\n" );
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document.write( "substitute this into any of the above, to get y = 12\r<BR>\n" );
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document.write( "so the three terms are\r<BR>\n" );
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document.write( "5   12   and  19<BR>\n" );
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