document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760616>Question 760616</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 3 times as old as his daughter, 8 years ago the product of their ages is 112, find their present ages  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462764 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Good problem. <BR>\n" );
document.write( "Setting up the 2 equations correctly is the key. Let \"m\" represent man and \"d\" for daughter:<BR>\n" );
document.write( "m=3d<BR>\n" );
document.write( "(m-8)(d-8)=112<BR>\n" );
document.write( "Substitute to get:<BR>\n" );
document.write( "(3d-8)(d-8)=112<BR>\n" );
document.write( "Expand out to:<BR>\n" );
document.write( "3d^2-32d+64=112<BR>\n" );
document.write( "Rewritten as:<BR>\n" );
document.write( "3d^2-32d-48=0<BR>\n" );
document.write( "Use quadratic Formula and we get:<BR>\n" );
document.write( "d=12<BR>\n" );
document.write( "So the father is 36 years old. <BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );