document.write( "Question 760604: Factor the given polynomial
\n" ); document.write( "X^2+4x+3=\r
\n" ); document.write( "\n" ); document.write( "Is this polynomial a prime or can it be sloved. Also can someone break this down for me so I can see how to work it. Thanks
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Algebra.Com's Answer #462744 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
You are looking for two numbers, h and k, so that hk=3 and h+k=4. You need for h and k to be rational numbers or preferably integers. Based on the signs in the given polynomial, both h and k must be positive. Your only choice (for integers) is 3 and 1 which will work.\r
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\n" ); document.write( "\n" ); document.write( "Another structuring of the search:
\n" ); document.write( "\"%28x%2Bh%29%28x%2Bk%29\"=?
\n" ); document.write( "\"x%5E2%2Bhx%2Bkx%2Bhk\"
\n" ); document.write( "\"x%5E2%2B%28h%2Bk%29x%2Bhk\"
\n" ); document.write( "How can \"x%5E2%2B%28h%2Bk%29x%2Bhk=x%5E2%2B4x%2B3\" ?\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x%2B3\" is factorable.
\n" ); document.write( "If let h=3, and k=1, then you have
\n" ); document.write( "\"highlight%28%28x%2B1%29%28x%2B3%29%29\"
\n" ); document.write( "Because 3*1=3 and 1+3=4
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