document.write( "Question 760604: Factor the given polynomial
\n" ); document.write( "X^2+4x+3=\r
\n" ); document.write( "\n" ); document.write( "Is this polynomial a prime or can it be sloved. Also can someone break this down for me so I can see how to work it. Thanks
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Algebra.Com's Answer #462739 by Stitch(470)\"\" \"About 
You can put this solution on YOUR website!
First find the factors of 1 from the \"X%5E2\"
\n" ); document.write( "The factors of 1 are: 1,1
\n" ); document.write( "Next Find the factors of 3 (the constant)
\n" ); document.write( "The factors of 3 are: 1,3
\n" ); document.write( "Note that the 3 is positive that means that the factors have to both be positive or both negative.
\n" ); document.write( "Now use the factors of 1 and the factors of 3 to come up with the 4X
\n" ); document.write( "1*3 + 1*1 = 4
\n" ); document.write( "So \"X%5E2+%2B+4X+%2B+3\" can be rewritten as \"%28X+%2B+3%29%2A%28X+%2B+1%29\"
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\n" ); document.write( "Now we have to solve for each part of the equation.
\n" ); document.write( "The equation equals zero when either of the parentheses equal zero.
\n" ); document.write( "\"X+%2B+3+=+0\"
\n" ); document.write( "Subtract 3 from both sides
\n" ); document.write( "\"highlight%28X+=+-3%29\"
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\n" ); document.write( "\"X+%2B+1+=+0\"
\n" ); document.write( "Subtract 1 from both sides
\n" ); document.write( "\"highlight_green%28X+=+-1%29\"
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