document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760531>Question 760531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of one of two adjacent angles is 116 degree more than thrice the other . find the measure of both angles if this sum is 140 degree<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462707 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the measure of one of two adjacent angles is 116 degree more than thrice the other . find the measure of both angles if this sum is 140 degree<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "a + b = 140 degrees<BR>\n" );
document.write( "a = 3b+116<BR>\n" );
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document.write( "Substitute for \"a\" and solve for \"b\":<BR>\n" );
document.write( "3b+116 + b = 140<BR>\n" );
document.write( "4b = 24<BR>\n" );
document.write( "b = 6 degrees<BR>\n" );
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document.write( "a + b = 140<BR>\n" );
document.write( "a + 6 = 140<BR>\n" );
document.write( "a = 134 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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