document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760520>Question 760520</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the area of a sector of a circle of radius 10 cm. is 200 sq. cm., find the central angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462694 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the area of a sector of a circle of radius 10 cm. is 200 sq. cm., find the central angle.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Total area = (pi)*10^2 = 100pi sq.cm.<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "sector fraction: 200/(100pi) = 2/pi <BR>\n" );
document.write( "------<BR>\n" );
document.write( "Central angle = (2/pi)(360) = 229.31 degrees<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );