document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760475>Question 760475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 100 green tickets and 10 red tickets are sold in a raffle in which there are three prizes.. one ticket is drawn for first prizes, discarded, and then a second ticket is drawn for second prize. this is also discarded before the third prize is drawn.<BR>\n" );
document.write( "a) what is the probability that all three prizes are won by green tickets?<BR>\n" );
document.write( "b) what is the probability that at least one green tickets wins a prize? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462690 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> probability of drawing a green ticket on the first draw is 100/110.<BR>\n" );
document.write( "probability of drawing a green ticket on second draw assuming you drew a green ticket on the first draw is 99/109.<BR>\n" );
document.write( "probability of drawing a green ticket on third draw assuming you drew a green ticket on the first and second draw is 98/108.\r<BR>\n" );
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document.write( "the combined probability of getting a green ticket on all 3 draws is equal to  100/110 * 99/109 * 98/108.\r<BR>\n" );
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document.write( "pobability of drawing at least 1 green ticket on all 3 draws is equal to 1 minus the probability of drawing 0 green tickets on all 3 draws.\r<BR>\n" );
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document.write( "the probability of getting 0 green ticket on all 3 draws is the same as the probability of getting a red ticket on all 3 draws.\r<BR>\n" );
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document.write( "p(red) on dirst draw is 10/110.<BR>\n" );
document.write( "p(red) on second draw assuming you got a red ticket on first draw is 9/109.<BR>\n" );
document.write( "p(red) on third draw is assuming you got a red ticket on first and second draw is 8/108.\r<BR>\n" );
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document.write( "combined probability of getting a red ticket on all 3 draws is equal to 10/110 * 9/109 * 8/108.\r<BR>\n" );
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document.write( "combined probability of getting 0 green ticket on all 3 draws is the same probability as the probability of getting a red ticket on all 3 draws.\r<BR>\n" );
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document.write( "probability of getting at least 1 green ticket on all 3 draws is equal to 1 minus the probability of getting 0 green tickets on all 3 draws which is equal to 1 minus (10/110 * 9/109 * 8/108).\r<BR>\n" );
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document.write( " </SPAN>\n" );
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