document.write( "Question 760488: If we toss two fair coins simultaneously what is the probability of getting exactly one Head? \n" ); document.write( "

Algebra.Com's Answer #462682 by ramkikk66(644) $\"\"$ $\"About$

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If we toss 2 coins simultaneously, the possible outcomes are as follows.
\n" ); document.write( "(where H = heads, T = tails)\r
\n" ); document.write( "\n" ); document.write( "If Coin1 shows Heads and Coin2 shows Heads, let us represent it as (H,H)\r
\n" ); document.write( "\n" ); document.write( "If Coin1 shows Heads and Coin2 shows Tails, let us represent it as (H,T)\r
\n" ); document.write( "\n" ); document.write( "Thus, we have the following combinations:
\n" ); document.write( "(H,H) (T,T), (H,T), (T,H) - exactly 4 possible results.\r
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\n" ); document.write( "\n" ); document.write( "From the above, you can see that exactly 2 of the 4 outcomes have \"exactly one head\" i.e. (H,T) and (T,H)\r
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\n" ); document.write( "\n" ); document.write( "As you know, probability is defined as
\n" ); document.write( " $\"Number+of+favourable+outcomes+%2F+Total+number+of+possible+outcomes+\"$ \r
\n" ); document.write( "\n" ); document.write( "In this case, getting \"exactly one head\" is the favourable outcome.\r
\n" ); document.write( "\n" ); document.write( "Hence the probability of getting exactly one head is $\"+2+%2F+4+=+0.5+\"$
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