document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760485>Question 760485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2cos2x = 4cosx - 3, 0<= x <= 360\r<BR>\n" );
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document.write( "Hi, I'm stuck on this trig question I've tried substituting in a few things but they just dont seem to work... :/ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462678 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2cos2x = 4cosx - 3<BR>\n" );
document.write( "2(2cos^2x - 1) = 4cosx - 3<BR>\n" );
document.write( "4cos^2x - 2 = 4cosx - 3<BR>\n" );
document.write( "4cos^2 x - 4cosx + 1 = 0<BR>\n" );
document.write( "(2cosx - 1)(2cosx - 1) = 0<BR>\n" );
document.write( " 2cosx - 1 = 0<BR>\n" );
document.write( " 2cosx = 1<BR>\n" );
document.write( "  cosx = 1/2<BR>\n" );
document.write( "     x = 60 degs and 300 degs<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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