document.write( "Question 760253: Find the exact value of
\n" ); document.write( "1.)y=tan inverse 1.)
\n" ); document.write( "2)y=cos inverse (-1)
\n" ); document.write( "3.)y=tan inverse (-1)
\n" ); document.write( "4)y=sec inverse 1
\n" ); document.write( "5.)y=arcsec (2 sqrt3/3)
\n" ); document.write( "6)y =sec inverse 1
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Algebra.Com's Answer #462660 by lwsshak3(11628)\"\" \"About 
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Find the exact value of
\n" ); document.write( "1.)y=tan inverse 1.)=π/4
\n" ); document.write( "2)y=cos inverse (-1)=π
\n" ); document.write( "3.)y=tan inverse (-1)=3π/4
\n" ); document.write( "4)y=sec inverse 1=0
\n" ); document.write( "5.)y=arcsec (2 sqrt3/3)=π/6
\n" ); document.write( "6)y =csc inverse 1=π/2 (I changed the problem from sec to csc)
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