document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760453>Question 760453</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in 8 years he will be 5 times as old as he was 12 years ago. how old is he now?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462637 by </B><A HREF=/tutors/aboutme.mpl?userid=aquacean><B>aquacean(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aquacean><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=aquacean><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462637\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Methods:<BR>\n" );
document.write( "a. \"scratchpad\"<BR>\n" );
document.write( "b. \"orthodox\" (algebra stuff)\r<BR>\n" );
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document.write( "A.\r<BR>\n" );
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document.write( "8 + 12 = 20<BR>\n" );
document.write( "20 / 4 = 5<BR>\n" );
document.write( "5 * 5 = 25<BR>\n" );
document.write( "25 - 8 = 17\r<BR>\n" );
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document.write( "I added 8 years after and 12 years before (which sums uo to 20) to find out how many years it take for him to be five times his age. I divided 20 by 4 (which equated to 5) as 20 is 4/5 of his age 8 years after. And since 20 is 4/5 of his age 8 years after, the other 1/5 is 5. 25 is his age 8 years after. Subtract 8 then you get his present age now which is 17. \r<BR>\n" );
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document.write( "B. (This is the \"formal\" solution teachers accept)<BR>\n" );
document.write( "a = his present age\r<BR>\n" );
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document.write( "a = 5((12 + 8)/4) - 8<BR>\n" );
document.write( "a = 5(20/4) - 8<BR>\n" );
document.write( "a = 25 - 8<BR>\n" );
document.write( "a = 17 </SPAN>\n" );
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