document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760411>Question 760411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A person has three times as many two dollar coin in his pocket as one dollar coins.The total value of these coins is $49. How many coins of each kind has he? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462623 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of $2 coins<BR>\n" );
document.write( "Let y = the number of $1 coins<BR>\n" );
document.write( "We can write two equations, one for the number of coins and the other for the total value of the coins. For the number of coins we have<BR>\n" );
document.write( "(1) x = 3*y<BR>\n" );
document.write( "For the value we have<BR>\n" );
document.write( "(2) 2*x + 1*y = 49<BR>\n" );
document.write( "Now put x of (1) into (2) and get<BR>\n" );
document.write( "(3) 2*(3*y) + y = 49 or<BR>\n" );
document.write( "(4) 7*y = 49 or<BR>\n" );
document.write( "(5) y = 7<BR>\n" );
document.write( "Then using (1) we get<BR>\n" );
document.write( "(6) x = 3*7 or<BR>\n" );
document.write( "(7) x = 21<BR>\n" );
document.write( "Let's check using (2).<BR>\n" );
document.write( "Is (2*21 + 1*7 = 49)?<BR>\n" );
document.write( "Is (42 + 7 = 49)?<BR>\n" );
document.write( "Is (49 = 49)? Yes<BR>\n" );
document.write( "Answer: The person has 21 two dollar coins and 7 one dollar coins.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );