document.write( "Question 760319: A circular swimming pool is 18.6 ft in diameter and 4.2 ft deep.\r
\n" ); document.write( "\n" ); document.write( "a. Determine the volume, v, of the pool in gallons if one gallon is 231 cubic inches.\r
\n" ); document.write( "\n" ); document.write( "b. The pool's filter pump can circulate 2500 gal per hour. how many hours, t, do I need to run the filter in order to to filter the number of gallons contained in the pool?\r
\n" ); document.write( "\n" ); document.write( "c. one pound of chlorine shock treatment can treat 10000 gal. how much of the shock treatment, n, should I use?\r
\n" ); document.write( "\n" ); document.write( "I would really appreciate if you can help me with this question, i'm stuck with it for two days now\r
\n" ); document.write( "\n" ); document.write( "thank you
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Algebra.Com's Answer #462559 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
Part a)
\n" ); document.write( "convert the diameter and depth of the pool to inches
\n" ); document.write( "diameter = 18.6 * 12 = 223.2 inches and radius is 1/2 of this = 111.6 inches
\n" ); document.write( "depth = 4.2 * 12 = 50.4 inches
\n" ); document.write( "volume (v) = pi * 111.6^2 * 50.4 = 1.972802 * 10^6 cubic inches
\n" ); document.write( "v (in gallons) = 1972802 / 231 = 8540 gallons
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\n" ); document.write( "Part b)
\n" ); document.write( "t = 8540 / 2500 = 3.4 hours necessary to run filter
\n" ); document.write( "=================================================================
\n" ); document.write( "Part c)
\n" ); document.write( "n = 8540 / 10000 = .85 lbs of chlorine is necessary
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