document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760323>Question 760323</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have a picture frame that is 12ft in length and 5ft in width with a support bar running diagonally how do I figure the length of the support bar </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462558 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use Pythagoras.<BR>\n" );
document.write( "Length^2 + Width^2 = Diagonal^2<BR>\n" );
document.write( "12^2 + 5^2 = Diagonal^2<BR>\n" );
document.write( "Diagonal^2 = 169ft<BR>\n" );
document.write( "Diagonal = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28169%29 ALIGN=MIDDLE  ALT=\"sqrt%28169%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Diagonal = 13ft.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );