document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760267>Question 760267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three solid spherical balls of diameters 10, 8 and 6cm Respectively are melted into one solid ball.               what will be the diameter of new ball......?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462516 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Volume(V) of a ball is 4/3 * pi * radius^3<BR>\n" );
document.write( "V of new ball = 4/3 *pi *5^3 + 4/3 *pi * 4^3 +4/3 *pi *3^3 (radius is 1/2 diameter)<BR>\n" );
document.write( "factor 4/3 and pi from equation<BR>\n" );
document.write( "V of new ball = 4/3*pi*(5^3 +4^3 + 3^3)<BR>\n" );
document.write( "V of new ball = 4/3*pi*216 = 905.14<BR>\n" );
document.write( "notice that 6^3 = 216, so the diameter of the new ball is 6*2 = 12cm\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );