document.write( "Question 65597This question is from textbook An Incremental Development
\n" ); document.write( ": Ortiz drives twice as fast as his brother and therefore makes the 350-mile trip home in 5 hours less time. How fast does each drive, and for how long does each travel? \n" ); document.write( "
Algebra.Com's Answer #46249 by ptaylor(2198)\"\" \"About 
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Let r= Oritz brothers rate of speed
\n" ); document.write( "Then 2r=Ortiz rate of speed\r
\n" ); document.write( "\n" ); document.write( "We'll let t=Oritz brothers time for the trip
\n" ); document.write( "Then t-5=Ortiz time for the trip\r
\n" ); document.write( "\n" ); document.write( "Now we know that distance (d)=rate(r) times time (t)\r
\n" ); document.write( "\n" ); document.write( "We also know that d=350 mi\r
\n" ); document.write( "\n" ); document.write( "(r)(t) =distance Ortiz brother travels =350 mi
\n" ); document.write( "2r(t-5)=distance Ortiz travels =350 mi\r
\n" ); document.write( "\n" ); document.write( "So our equations to solve are:
\n" ); document.write( " rt=350
\n" ); document.write( "2r(t-5)=350
\n" ); document.write( " Since both equations equal 350 mi we have:
\n" ); document.write( "rt=2r(t-5)
\n" ); document.write( "rt=2rt-10r simplifying we have:
\n" ); document.write( "2rt-rt=10r
\n" ); document.write( "rt=10r
\n" ); document.write( "t=10 hours Ortiz brothers travel time
\n" ); document.write( "t-5=10-5=5 hours Ortiz travel time\r
\n" ); document.write( "\n" ); document.write( "Now rt=350
\n" ); document.write( "r(10)=350
\n" ); document.write( "r=35 MPH Oritz brothers rate of speed\r
\n" ); document.write( "\n" ); document.write( "2r=2(35)=70 MPH Ortiz rate of speed\r
\n" ); document.write( "\n" ); document.write( "Ck\r
\n" ); document.write( "\n" ); document.write( "By inspection we see that Ortiz travelled twice as fast and made the trip in five hours less time than his brother\r
\n" ); document.write( "\n" ); document.write( "Hope this helps -----ptaylor\r
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