document.write( "Question 760134: If a person has 50 coins in their pocket that adds up to 1.00 dollar, how many coins of each denominations are in their pocket? \n" ); document.write( "
Algebra.Com's Answer #462448 by josmiceli(19441)\"\" \"About 
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There can't be 4 quarters, since that = $1
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\n" ); document.write( "There can't be 3 quarters, since the most number of
\n" ); document.write( "coins would then be 3 quarters + 25 pennies, and
\n" ); document.write( "that is only 28 coins
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\n" ); document.write( "If there are 2 quarters, the largest number of coins
\n" ); document.write( "is 2 quarters + 50 pennies = 52 coins. If you subtract
\n" ); document.write( "2 pennies, you only have \"+2%2A25+%2B+48+=+98+\" cents
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\n" ); document.write( "If there is 1 quarter, I'll try
\n" ); document.write( "1Q
\n" ); document.write( "40P
\n" ); document.write( "2D
\n" ); document.write( "3N
\n" ); document.write( "That is $1, but only 46 coins
\n" ); document.write( "I'll try
\n" ); document.write( "1Q
\n" ); document.write( "40P
\n" ); document.write( "1D
\n" ); document.write( "5N
\n" ); document.write( "That's $1 and 47 coins
\n" ); document.write( "1Q
\n" ); document.write( "40P
\n" ); document.write( "7N
\n" ); document.write( "That's $1 and 48 coins
\n" ); document.write( "1Q
\n" ); document.write( "45P
\n" ); document.write( "1D
\n" ); document.write( "4N
\n" ); document.write( "That's $1 and 51 coins
\n" ); document.write( "1Q
\n" ); document.write( "45P
\n" ); document.write( "2D
\n" ); document.write( "2N
\n" ); document.write( "That's $1 and 50 coins
\n" ); document.write( "OK\r
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