document.write( "Question 760129: Determine the vertex of the parabola whose equation is (y-1)^2=16(x-4) \n" ); document.write( "

Algebra.Com's Answer #462447 by lwsshak3(11628) $\"\"$ $\"About$

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Determine the vertex of the parabola whose equation is
\n" ); document.write( "(y-1)^2=16(x-4)
\n" ); document.write( "change equation to standard (vertex) form: x=A(y-k)^2+h, (h,k)=(x,y) coordinates of vertex, A is a coefficient that affects the slope or steepness of the curve.
\n" ); document.write( "(y-1)^2=16(x-4)
\n" ); document.write( "(y-1)^2=16x-64
\n" ); document.write( "(y-1)^2+64=16x
\n" ); document.write( "16x=(y-1)^2+64
\n" ); document.write( " $\"x=%28y-1%29%5E2%2F16%2B4\"$
\n" ); document.write( "This is an equation of a parabola that opens rightward with vertex at (4,1) \n" ); document.write( "

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