document.write( "Question 758678: If sinx+cosx = 1/2, then tanx+cotx = ? \n" ); document.write( "
Algebra.Com's Answer #462426 by tommyt3rd(5050)\"\" \"About 
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we rewrite:
\n" ); document.write( "\"%0D%0Atanx%2Bcotx+=+sin%28x%29%2Fcos%28x%29%2Bsin%28x%29%2Fcos%28x%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Atanx%2Bcotx=1%2F%28sin%28x%29cos%28x%29%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "Next we can square the given equation:\r
\n" ); document.write( "\n" ); document.write( "\"%0D%0Asin%28x%29%2Bcos%28x%29+=+1%2F2\" \r
\n" ); document.write( "\n" ); document.write( "to get...\r
\n" ); document.write( "\n" ); document.write( "\"%0D%0Asin%5E2%28x%29%2B2sin%28x%29cos%28x%29%2Bcos%5E2%28x%29+=+1%2F4%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "and after simplifying we get
\n" ); document.write( "\"sin%28x%29cos%28x%29=-3%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "which means\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Atanx%2Bcotx=-8%2F3%0D%0A\"
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