document.write( "Question 760068: In a list of consuctive odd integers, three times the first number is equal to three more than twice than twice the third number. Find the third number? \n" ); document.write( "

Algebra.Com's Answer #462417 by KMST(5328) $\"\"$ $\"About$

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In a list of consecutive integers you may find
\n" ); document.write( "...., n-3, n-2, n-1, n, n+1, n+2, n+3, ...., in that order.
\n" ); document.write( "In a list of consecutive odd (or even) integers you find
\n" ); document.write( "...., n-6, n-4, n-2, n, n+2, n+4, n+6, ...., in that order.
\n" ); document.write( "So if the third of your consecutive odd integers were $\"n\"$ ,
\n" ); document.write( "the first would be $\"n-4\"$ , and the second would be $\"n-2\"$ .
\n" ); document.write( "Three times the first would be $\"3%28n-4%29\"$ and
\n" ); document.write( "three more than twice than twice the third number would be $\"2n%2B3\"$
\n" ); document.write( "Then, $\"3%28n-4%29=2n%2B3\"$ --> $\"3n-12=2n%2B3\"$ --> $\"3n=2n%2B3%2B12\"$ --> $\"3n-2n=3%2B12\"$ --> $\"highlight%28n=15%29\"$ \n" ); document.write( "

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