document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=760080>Question 760080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A river 2 m deep and 20 m wide is flowing at the rate of 5.4 km per<BR>\n" );
document.write( "hour. How much water will fall into the sea in 3 minutes. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462407 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5.4km/hr = 90m/min<BR>\n" );
document.write( "If we give the water a length of 1 metre<BR>\n" );
document.write( "the volume will be 2 x 20 x 1 = 40 m^3<BR>\n" );
document.write( "Running at 90m/min <BR>\n" );
document.write( "In 3 mins = 90 * 40 * 3<BR>\n" );
document.write( "= 10800m^3 in 3 mins<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );