document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759980>Question 759980</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a positive number of two digits, the tens place exceeds the unit digit by 5. if the product of the digit is 36 find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462345 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the tens place exceeds the unit digit by 5.<BR>\n" );
document.write( "say the units place is x so the tens place is x+5<BR>\n" );
document.write( "the product of the digit is 36 <BR>\n" );
document.write( "so x(x+5)=36<BR>\n" );
document.write( "or x^2+5x-36=0<BR>\n" );
document.write( "or x^2+9x-4x-36=0<BR>\n" );
document.write( "or x(x+9)-4(x+9)=0<BR>\n" );
document.write( "or (x+9)(x-4)=0<BR>\n" );
document.write( "or x=-9 or 4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );