document.write( "Question 759994: Triangle ABC has its coordinates at A(a, -1), B(8, -1) and C(5,4). If the base is twice the height, find a. \n" ); document.write( "

Algebra.Com's Answer #462330 by josgarithmetic(39617) $\"\"$ $\"About$

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The base may be contained on the lower, horizontal line of $\"y=-1\"$ . The highest point is C, so the height for the triangle is |-1|+|4|=5.\r
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\n" ); document.write( "\n" ); document.write( "Given: Base is twice the height, so using b for base, h for height, h=5 and so $\"b=2%2A5=10\"$ .
\n" ); document.write( "Base is 10 units. \r
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\n" ); document.write( "\n" ); document.write( "Consider the horizontal line again. One end point for the base is B(8,-1). We want 'a' where A is 10 units away from B. There are two choices for this. You can choose either $\"a=8%2B10\"$ or $\"a=8-10\"$ . Both will work. \n" ); document.write( "

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