document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64813>Question 64813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sqaure root of 2 - 3 over square root of 3 - 7\r<BR>\n" );
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document.write( "the other question is <BR>\n" );
document.write( "(4 sqaure root of 2 - square root of 6)(square root of 2 + 4 sqaure root of 6) and on the V section of the sqaure roots there is a 5 on the outside of V\r<BR>\n" );
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document.write( "also (2m-5)2 power =49 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46227 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SQRT(2-3)/SQRT(3-7)<BR>\n" );
document.write( "SQRT-1/SQRT-4<BR>\n" );
document.write( "1i/2i<BR>\n" );
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document.write( "DON'T UNDERSTAND THIS PROBLEM<BR>\n" );
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document.write( "(2M-5)^2=-49<BR>\n" );
document.write( "4M^2-20M+25=-49<BR>\n" );
document.write( "4M^2-20M+25+49=0<BR>\n" );
document.write( "4M^2-20M+74<BR>\n" );
document.write( "FORMULA<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X=%2820%2B-SQRT%28-20%5E2-4%2A4%2A74%29%29%2F%282%2A4%29 ALIGN=MIDDLE  ALT=\"X=%2820%2B-SQRT%28-20%5E2-4%2A4%2A74%29%29%2F%282%2A4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "=(20+-SQRT(400-1184))/8 <BR>\n" );
document.write( "=(20+-sqrt-784)/8<BR>\n" );
document.write( "=(20+-28i)/8<BR>\n" );
document.write( "=(20/8+-28i)/8<BR>\n" );
document.write( "=2.5+-3.5i<BR>\n" );
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document.write( "MERRY CHRISTMAS<BR>\n" );
document.write( " </SPAN>\n" );
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