document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759816>Question 759816</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation for the line that passes through the point (3, 5) and that is parallel to the line with the equation (y-1)=-1/3 (×-3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462251 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Put into form y = mx + c<BR>\n" );
document.write( "(y - 1) = -1/3(x - 3)<BR>\n" );
document.write( "    y  = -1/3x + 1 + 1<BR>\n" );
document.write( "     y = -1/3x + 2<BR>\n" );
document.write( "All lines that are parallel have the same gradient i.e. -1/3<BR>\n" );
document.write( "Using y - b = m(x - a)<BR>\n" );
document.write( "      y - 5 = -1/3(x - 3)<BR>\n" );
document.write( "      y - 5 = -1/3x + 1 <BR>\n" );
document.write( "          y = -1/3x + 1 + 5<BR>\n" );
document.write( "          y = -1/3x + 6<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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