document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759814>Question 759814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to find decimals from radical ? plz solve this one &#8730;27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462235 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how to find decimals from radical ? plz solve this one &#8730;27<BR>\n" );
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document.write( "Note: 27 is not a perfect square.  Therefore, it's square<BR>\n" );
document.write( "root is an irrational number.  Irrational numbers can only<BR>\n" );
document.write( "be approximated using decimal notation.<BR>\n" );
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document.write( "sqrt(27) = sqrt(9*3) = 3sqrt(3) = 3(1.7321...) = 5.1962...<BR>\n" );
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document.write( "Finding sqrt(3)<BR>\n" );
document.write( "Since 3 is between 1 and 4, sqrt(3) is between sqrt(1) and sqrt(4).<BR>\n" );
document.write( "So, sqrt(3) is at least 1 and it is less than 2.<BR>\n" );
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document.write( "Try sqrt(3) = 1.5<BR>\n" );
document.write( "1.5^2 = 2.25 which is less than 3<BR>\n" );
document.write( "Try sqrt(3) = 1.75<BR>\n" );
document.write( "1.75^2 = 3.0625 which is very close to 3<BR>\n" );
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document.write( "At this point you could try 1.74<BR>\n" );
document.write( "1.74^2 = 3.0276 which is even closer to 3<BR>\n" );
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document.write( "Try 1.73^2 = 2.9929<BR>\n" );
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document.write( "Now you know 1.73 < sqrt(3)< 1.74<BR>\n" );
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document.write( "You could carry this on forever to get addition decimal places,<BR>\n" );
document.write( "but you will never be able to find a decimal form for sqrt(3)<BR>\n" );
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document.write( "Hope that helps.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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