document.write( "Question 759800: a box contains 12 balls of which 4 are green and 8 are red. if 7 balls are drawn from the box at random, one by one with replacement, find the probability that exactily 3 balls drawn are green. \n" ); document.write( "
Algebra.Com's Answer #462227 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! a box contains 12 balls of which 4 are green and 8 are red. if 7 balls are drawn from the box at random, one by one with replacement, find the probability that exactily 3 balls drawn are green. \n" ); document.write( " \n" ); document.write( "First we will find the probability of drawing the 7 in this particular order: \n" ); document.write( "GGGRRRR, where G = drawing a green ball and R = drawing a red ball. \n" ); document.write( "That is, \n" ); document.write( " \n" ); document.write( "But they do not have to be chosen in the particular order GGGBBBB. \n" ); document.write( "For instance, the order BBGBGBG or GBGBGBB would do just as well. \n" ); document.write( "So we must multiply the probability of the particular order GGGBBBB \n" ); document.write( "by the number of all possible orders. That is the number of ways to \n" ); document.write( "choose 3 of the 7 positions to draw the 3 green balls in or \n" ); document.write( "C(7,3) = 35. (The other 4 positions will of course be red balls). \n" ); document.write( "So the answer is \n" ); document.write( " \n" ); document.write( "Edwin \n" ); document.write( " |