document.write( "Question 759570: A square with an area of 49 in. To the second power had a perimeter of________.
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document.write( " I tried solving it i don't know if its correct.
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document.write( "49 in. To the second power =2401/4= 600.25·4= 2401 so the perimeter is 2401. Is that correct? \n" );
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Algebra.Com's Answer #462220 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! A square with an area of 49 ins^2 \n" ); document.write( " has a perimeter of 28 ins. \n" ); document.write( "Area of square = length^2 \n" ); document.write( "Length^2 = 49 \n" ); document.write( "Therefore length = square root of 49 \n" ); document.write( " length = 7 ins \n" ); document.write( "Perimeter = 2*length + 2* width \n" ); document.write( "(With a square, length = width) \n" ); document.write( " = 2*7 + 2*7 \n" ); document.write( " = 28 ins. \n" ); document.write( "I think you are confusing the second power. \n" ); document.write( "The second power is associated with inches \n" ); document.write( "i.e. 49 ins^2 was the area. \n" ); document.write( "Hope this helps,. \n" ); document.write( ":-) \n" ); document.write( " \n" ); document.write( " |