document.write( "Question 759621: An express bus travels a certain 320km route in 1hr less time than it takes a local buss to travel a 300km route. Find the speed of each bus if the speed of the local is 20km/h less than that of the express. \n" ); document.write( "
Algebra.Com's Answer #462205 by sachi(548)\"\" \"About 
You can put this solution on YOUR website!
the speed of the local is 20km/h less than that of the express
\n" ); document.write( "so let the speed of the express bus=x & that of local=x-20
\n" ); document.write( "An express bus travels a certain 320km route in 1hr less time than it takes a local buss to travel a 300km route.
\n" ); document.write( "so time taken by both bussed are
\n" ); document.write( "the express took 320/x & the local took 300/(x-20)
\n" ); document.write( "as per question
\n" ); document.write( "300/(x-20)-320/x=1
\n" ); document.write( "or 300x-320(x-20)=x(x-20) multiplying x)x-20) on both sides
\n" ); document.write( "or 300x-320x+6400=x^2-20x
\n" ); document.write( "or -20x+6400=x^2-20x
\n" ); document.write( "or x^2=6400
\n" ); document.write( "or x=80 kmph= speed of express
\n" ); document.write( "& the speed of local=80-20=60 kmph
\n" ); document.write( "
\n" );