document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759771>Question 759771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the equations x^2+2x-3=0 & x^2+3x-k=0 have a comman root then the non-zero value of k is: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462198 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the equations x^2+2x-3=0 & x^2+3x-k=0 have a comman root then the non-zero value of k is:<BR>\n" );
document.write( "let us solve the eqn<BR>\n" );
document.write( "x^2+2x-3=0<BR>\n" );
document.write( "or x^2+3x-x-3=0<BR>\n" );
document.write( "or x(x+3)-1(x+3)=0<BR>\n" );
document.write( "or (x+3)(x-1)=0<BR>\n" );
document.write( "x= -3 Or 1<BR>\n" );
document.write( "now the 2nd eqn<BR>\n" );
document.write( "x^2+3x-k=0<BR>\n" );
document.write( "the roots x={-3+/-sqrt[3^2-4*1*-k]}/2=-3 Or 1<BR>\n" );
document.write( "or ={-3+/-sqrt[3^2-4*1*-k]}=-6 or 2   multiplying 2 on RHS<BR>\n" );
document.write( "or +/-sqrt[3^2-4*1*-k]}=-3 or 5       adding 3 on RHS<BR>\n" );
document.write( "or 3^2-4*1*-k=9 or 25                 squaring both sides<BR>\n" );
document.write( "or 9+4k=9 or 25                       simplifying<BR>\n" );
document.write( "or 4k=0 or 16                         subtracting 9 on RHS<BR>\n" );
document.write( "or k=0 or 4                           dividing 4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );