document.write( "Question 759731: The height of a rocket, in feet above the ground, t seconds after it was launched is given by the expression 25 + 150t - 16t 2 second power. How many feet above the ground is the rocket 3 seconds after it was launched? \n" ); document.write( "

Algebra.Com's Answer #462186 by josmiceli(19441) $\"\"$ $\"About$

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$\"+h+=+-16t%5E2+%2B+150t+%2B+25+\"$
\n" ); document.write( " $\"+t+=+3+\"$
\n" ); document.write( " $\"+h+=+-16%2A3%5E2+%2B+150%2A3+%2B+25+\"$
\n" ); document.write( " $\"+h+=+-16%2A9+%2B+450+%2B+25+\"$
\n" ); document.write( " $\"+h+=+-144+%2B+475+\"$
\n" ); document.write( " $\"+h+=+331+\"$
\n" ); document.write( "The rocket is 331 ft above ground 3 sec after launch
\n" ); document.write( " \n" ); document.write( "

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