document.write( "Question 759702: Use the compound formula A=Pe^rt
\n" ); document.write( " To solve the problem given. Round answers to the nearest cent.
\n" ); document.write( "Find the accumulated value of an investment of $20,000 for 4 years at an interst rate of 4.5% if the money is
\n" ); document.write( "a. Compounded semi=annually ___(Round to the nearest cent)
\n" ); document.write( "b. What is the accumulated value if the money is compounded monthly? ___(Round to the nearest cent)
\n" ); document.write( "c. What is the accumulated value if the money is compounded continuously?
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Algebra.Com's Answer #462183 by lwsshak3(11628)\"\" \"About 
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Use the compound formula A=Pe^rt
\n" ); document.write( "To solve the problem given. Round answers to the nearest cent.
\n" ); document.write( "Find the accumulated value of an investment of $20,000 for 4 years at an interst rate of 4.5% if the money is
\n" ); document.write( "a. Compounded semi=annually ___(Round to the nearest cent)
\n" ); document.write( "b. What is the accumulated value if the money is compounded monthly? ___(Round to the nearest cent)
\n" ); document.write( "c. What is the accumulated value if the money is compounded continuously?
\n" ); document.write( "***
\n" ); document.write( "Compound Interest formula for fixed periods: A=P(1+i)^n, P=initial investment, i=interest rate per period, n=number of periods, A=amount after n periods.
\n" ); document.write( "..
\n" ); document.write( "Formula for continuous compounding: A=Pe^rt, P=initial investment, r=annual interest rate, t=number of years, A=amount after t years
\n" ); document.write( "..
\n" ); document.write( "a. Compounded semi=annually
\n" ); document.write( "P=$20000
\n" ); document.write( "i=.045/2=0.0225
\n" ); document.write( "n=4*2=8
\n" ); document.write( "A=20000(1+0.0225)^8
\n" ); document.write( "A=20000(1.0225)^8=$23,896.62
\n" ); document.write( "..
\n" ); document.write( "b. Compounded monthly
\n" ); document.write( "P=$20000
\n" ); document.write( "i=.045/12=0.00375
\n" ); document.write( "n=4*12=48
\n" ); document.write( "A=20000(1+0.00375)^48
\n" ); document.write( "A=20000(1.00375)^48=$23,936.29
\n" ); document.write( "..
\n" ); document.write( "c. Continuous compounding:
\n" ); document.write( "P=$20000
\n" ); document.write( "r=.045
\n" ); document.write( "n=4
\n" ); document.write( "A=20000*e^(.045*4)
\n" ); document.write( "A=20000*e^0.18=$23944.35
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