document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759750>Question 759750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Subtracting fraction please reduce and show work.\r<BR>\n" );
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document.write( "3-3/5-1-1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462177 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3-3/5-1-1/2 the LCM of 2 & 5=10<BR>\n" );
document.write( "so making all denominator=10<BR>\n" );
document.write( "3-3/5-1-1/2=3/1-3/5-1/1-1/2 becomes<BR>\n" );
document.write( "3*10/1*10-3*2/5*2-1*10/1*10-1*5/2*5<BR>\n" );
document.write( "=30/10-6/10-10/10-5/10=(30-6-10-5)/10=9/10=0.9 </SPAN>\n" );
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