document.write( "Question 759763: I have the equation $\"+x%5E4-134x%5E2%2B1125=0+\"$ and the answers $\"+-5sqrt%285%29+\"$ , -3,3, and $\"+5sqrt%285%29+\"$ . My question is how did it simplified all the way down from $\"+x%5E4-134x%5E2%2B1125=0+\"$ to x=-(-134)ąsqrt((-134)^2-4(1)(1125))÷2(1) to x=134ąsqrt(13456))÷2 to $\"+-5sqrt%285%29+\"$ , -3,3, and $\"+5sqrt%285%29+\"$ ?? \n" ); document.write( "

Algebra.Com's Answer #462169 by sachi(548) $\"\"$ $\"About$

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x^4-134x^2+1125=0
\n" ); document.write( "let us put x^2=y so the eqn converts to
\n" ); document.write( "y^2-134y+1125=0
\n" ); document.write( "or y^2-125y-9y+1125=0
\n" ); document.write( "or y(y-125)-9(y-125)=0
\n" ); document.write( "or (y-125)(y-9)=0
\n" ); document.write( "or y=125 or 9
\n" ); document.write( "or x^2=125 or 9
\n" ); document.write( "or x= sqrt(125) or sqrt9
\n" ); document.write( "or x={{ -5sqrt(5) }}} , -3,3, and $\"+5sqrt%285%29+\"$ \n" ); document.write( "

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