document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759668>Question 759668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a money box of 5c and 10c pieces there are 71 coins. Their total is $560. Find the number of each coin.\r<BR>\n" );
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document.write( "Im doing simultaneous equations which is where they give you 2 equations that have to be true at the same time like this:\r<BR>\n" );
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document.write( "4x + y = 9 and x - y =1<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462150 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462150\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the number of 5c coins, then 71-x is the number of 10c coins, and<BR>\n" );
document.write( "5x + 10*(71-x) = 560<BR>\n" );
document.write( "5x + 710 - 10x = 560<BR>\n" );
document.write( "-5x = -150<BR>\n" );
document.write( "x = 30\r<BR>\n" );
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document.write( "this means that there are 30 5c pieces and 41 10c pieces<BR>\n" );
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