document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759656>Question 759656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an artifact was found and tested for its carbon-14 content.  If 87% of the original carbon-14 was still present, what is its probably age (to the nearest 100 years)? (carbon-14 has a half-life of 5730 years.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462137 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> an artifact was found and tested for its carbon-14 content. If 87% of the original carbon-14 was still present, what is its probably age (to the nearest 100 years)? (carbon-14 has a half-life of 5730 years.)<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "0.87Ao = Ao*(1/2)^(t/5730)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(1/2)^(t/5730) = 0.87<BR>\n" );
document.write( "----<BR>\n" );
document.write( "(t/5730) = log(0.87)/log(1/2)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "t/5730 = 0.2009<BR>\n" );
document.write( "---<BR>\n" );
document.write( "t = 1151.23 years<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "====================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );