document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=759620>Question 759620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the standard form of the equation of the hyperbola with the given characteristics\r<BR>\n" );
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document.write( "1: vertices (0,+/-7) foci (0,+/-9)\r<BR>\n" );
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document.write( "2: vertices (0,+/-3) foci (0,+/-6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #462113 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=462113\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the standard form of the equation of the hyperbola with the given characteristics <BR>\n" );
document.write( "1: vertices (0,+/-7) foci (0,+/-9)<BR>\n" );
document.write( "hyperbola has a vertical transverse axis<BR>\n" );
document.write( "Its standard form of equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > , (h,k)=(x,y) coordinates of center<BR>\n" );
document.write( "For given hyperbola:<BR>\n" );
document.write( "center: (0,0)<BR>\n" );
document.write( "a=7 (distance from center to vertices)<BR>\n" );
document.write( "a^2=49<BR>\n" );
document.write( "c=9 (distance from center to vertices)<BR>\n" );
document.write( "c^2=81<BR>\n" );
document.write( "c^2=a^2+b^2<BR>\n" );
document.write( "b^2=c^2-a^2=81-49=32<BR>\n" );
document.write( "Equation of given hyperbola:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2F49-y%5E2%2F32=1 ALIGN=MIDDLE  ALT=\"x%5E2%2F49-y%5E2%2F32=1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "..<BR>\n" );
document.write( "2: vertices (0,+/-3) foci (0,+/-6)<BR>\n" );
document.write( "hyperbola has a vertical transverse axis<BR>\n" );
document.write( "Its standard form of equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1 ALIGN=MIDDLE  ALT=\"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > , (h,k)=(x,y) coordinates of center<BR>\n" );
document.write( "For given hyperbola:<BR>\n" );
document.write( "center: (0,0)<BR>\n" );
document.write( "a=3 (distance from center to vertices)<BR>\n" );
document.write( "a^2=9<BR>\n" );
document.write( "c=6 (distance from center to vertices)<BR>\n" );
document.write( "c^2=36 a^2+b^2<BR>\n" );
document.write( "b^2=c^2-a^2=36-9=25<BR>\n" );
document.write( "Equation of given hyperbola:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2F9-y%5E2%2F25=1 ALIGN=MIDDLE  ALT=\"x%5E2%2F9-y%5E2%2F25=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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