document.write( "Question 65568: Hi. \r
\n" ); document.write( "\n" ); document.write( "I have a problem with a rectangle being placed under the parabolic arch given by f(x)=27-3x^2 by using a point (x,y) on the parabola. Write a formula for the function A(x) that gives the area of the rectangle as a function of the x coordinate of the point chosen. \r
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Algebra.Com's Answer #46211 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
Hi.
\n" ); document.write( "I have a problem with a rectangle being placed under the parabolic arch given by f(x)=27-3x^2 by using a point (x,y) on the parabola. Write a formula for the function A(x) that gives the area of the rectangle as a function of the x coordinate of the point chosen.
\n" ); document.write( "Can anyone help?
\n" ); document.write( "QUESTION ISLACKING IN CLARITY.IF YOU FIX ONE POINT ON THE PARABOLA BY ITS X COORDINATE EQUAL TO H(SAY 2) THEN SINCE THE PARABOLA IS SYMMETRIC BOUT X=0 OR Y AXIS,-H (-2) IS ALSO A POINT ON THE PARABOLA AND THE RECTANGLE.
\n" ); document.write( "SO LENGTH =2H
\n" ); document.write( "BUT THEN WHAT IS THE WIDTH?.IF WE TRY TO TAKE ANOTHE POINT ON PARABOLA,IT WILL NOT BE A RECTANGLE BUT TRAPEZIUM.BUT THEN WHAT WIDTH IS TO BE CHOSEN?
\n" ); document.write( "IF NOT WE CAN TAKE A SQUARE.
\n" ); document.write( "THEN TS AREA IS 2H*2H=4H^2 IS HE AREA OF A SQUARE UNDER THE PARABOLIC ARCH WITH 2 POINTS ON IT.SEE GRAPH BELOW
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-100%2C+100%2C-21%2C24%2C27-3%2Ax%5E2%29+\"
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