document.write( "Question 65568: Hi. \r
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document.write( "I have a problem with a rectangle being placed under the parabolic arch given by f(x)=27-3x^2 by using a point (x,y) on the parabola. Write a formula for the function A(x) that gives the area of the rectangle as a function of the x coordinate of the point chosen. \r
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document.write( "Can anyone help? \n" );
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Algebra.Com's Answer #46211 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Hi. \n" ); document.write( "I have a problem with a rectangle being placed under the parabolic arch given by f(x)=27-3x^2 by using a point (x,y) on the parabola. Write a formula for the function A(x) that gives the area of the rectangle as a function of the x coordinate of the point chosen. \n" ); document.write( "Can anyone help? \n" ); document.write( "QUESTION ISLACKING IN CLARITY.IF YOU FIX ONE POINT ON THE PARABOLA BY ITS X COORDINATE EQUAL TO H(SAY 2) THEN SINCE THE PARABOLA IS SYMMETRIC BOUT X=0 OR Y AXIS,-H (-2) IS ALSO A POINT ON THE PARABOLA AND THE RECTANGLE. \n" ); document.write( "SO LENGTH =2H \n" ); document.write( "BUT THEN WHAT IS THE WIDTH?.IF WE TRY TO TAKE ANOTHE POINT ON PARABOLA,IT WILL NOT BE A RECTANGLE BUT TRAPEZIUM.BUT THEN WHAT WIDTH IS TO BE CHOSEN? \n" ); document.write( "IF NOT WE CAN TAKE A SQUARE. \n" ); document.write( "THEN TS AREA IS 2H*2H=4H^2 IS HE AREA OF A SQUARE UNDER THE PARABOLIC ARCH WITH 2 POINTS ON IT.SEE GRAPH BELOW \n" ); document.write( " |