document.write( "Question 759518: two are in the ratio of 8:3 if they differ by 50.find the number \n" ); document.write( "
Algebra.Com's Answer #462066 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
let numbers be \"x\" and \"y\"\r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"x%3Ay=8%3A3\"\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B50\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y%2B50%29%3Ay=8%3A3\"\r
\n" ); document.write( "\n" ); document.write( "\"3%28y%2B50%29=8y\"\r
\n" ); document.write( "\n" ); document.write( "\"3y%2B150=8y\"\r
\n" ); document.write( "\n" ); document.write( "\"150=8y-3y\"\r
\n" ); document.write( "\n" ); document.write( "\"150=5y\"\r
\n" ); document.write( "\n" ); document.write( "\"150%2F5=y\"\r
\n" ); document.write( "\n" ); document.write( "\"30=y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B50\"\r
\n" ); document.write( "\n" ); document.write( "\"x=30%2B50\"\r
\n" ); document.write( "\n" ); document.write( "\"x=80\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%3Ay=8%3A3\"\r
\n" ); document.write( "\n" ); document.write( "\"80%3A30=8%3A3\"
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