document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65577>Question 65577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If one-half of an interger is subtracted from three-fifths of the next consecutive interger, the difference is 3. What are the two intergers?\r<BR>\n" );
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document.write( "I am lost on trying to figure out this problem, I can solve them without the fractions but with confuse me horribly. Thank you for the help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46206 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3/5)(X+1)-X/2)=3<BR>\n" );
document.write( "(3X+3)/5-X/2=3<BR>\n" );
document.write( "[(3X+3)*2-5X]/10=3<BR>\n" );
document.write( "(6X+6-5X)/10=3<BR>\n" );
document.write( "X+6=30<BR>\n" );
document.write( "X=30-6<BR>\n" );
document.write( "X=24<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "(3/5)(24+1)-24/2=3<BR>\n" );
document.write( "3/5*25-12=3<BR>\n" );
document.write( "75/5-12=3<BR>\n" );
document.write( "15-12=3<BR>\n" );
document.write( "3=3<BR>\n" );
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document.write( "MERRY CHRISTMAS<BR>\n" );
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