document.write( "Question 759453: If a, b, c, d,e are five consecutive positive even integers. There average is?\r
\n" ); document.write( "\n" ); document.write( "If a, b, c, d, e, are five consecutive positive odd integers, There average is?
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Algebra.Com's Answer #462053 by maheswari2188(4)\"\" \"About 
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The numbers are a, b, c, d, e, f
\n" ); document.write( "As they are consecutive even integers they can be expressed as a, a+2, a+4, a+6, a+8. \r
\n" ); document.write( "\n" ); document.write( "Average = sum of the integers / Total Number of integers\r
\n" ); document.write( "\n" ); document.write( "ie, A = (a + a+2 + a+4 + a+6 + a+8)/ 5
\n" ); document.write( " A = (5a + 20)/ 5
\n" ); document.write( " A = 5(a + 4)/ 5 = a+4\r
\n" ); document.write( "\n" ); document.write( "2nd Part : same as above, as the difference between two consecutive odd integers are also 2.
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